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Finding the scalar equation of a plane

Formula for the scalar equation of a plane

To find the scalar equation of a plane, we’ll use the formula

???a(x-x_0)+b(y-y_0)+c(z-z_0)=0???

where ???P_0(x_0,y_0,z_0)??? is a given point and ???v=\langle a,b,c\rangle??? is the normal vector to the plane. The vector may also be in the format ???v=ai+bj+ck???.

How to find the scalar equation of a plane


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Scalar equation for a plane, given a vector and a point

Example

Find the scalar equation of the plane.

???P(1,4,-8)???

???\langle3,6,2\rangle???

Plugging the given point and the given vector into our formula, we get

???3(x-1)+6(y-4)+2\left[z-(-8)\right]=0???

???3(x-1)+6(y-4)+2(z+8)=0???

???3x-3+6y-24+2z+16=0???

???3x+6y+2z=11???

The scalar equation of the plane is given by ???3x+6y+2z=11???.


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