Determining whether or not a line integral is independent of path

 
 
Independence of path blog post.jpeg
 
 
 

What does it mean for a line integral to be independent of path?

Independence of path is a property of conservative vector fields. If a conservative vector field contains the entire curve ???C???, then the line integral over the curve ???C??? will be independent of path, because every line integral in a conservative vector field is independent of path, since all conservative vector fields are path independent.

Krista King Math.jpg

Hi! I'm krista.

I create online courses to help you rock your math class. Read more.

 

We can state the following facts:

  1. Conservative vector fields are independent of path

  2. Vector fields that are independent of path are conservative

As a result, the value of the line integral depends only on the endpoints of the curve ???C???, and not on the path taken by the integral between the endpoints.

No matter which path you follow between two points in a conservative vector field, whether it’s a direct, straight line, or a curvy, winding path, or any other path, the value of the line integral will be the same if the endpoints are the same.

That fact that conservative vector fields are independent of path makes finding the line integral of the vector field easy. All we need is the potential function ???f??? of the vector field ???F???, such that

???\bold{F}=\nabla f???

Once we find ???f???, we simply evaluate it over the interval defined by the endpoints of the curve ???C???, and our answer will be the value of the line integral of the vector field ???F???.

In other words, if the endpoints of the curve ???C??? are ???a??? and ???b??? or ???(x_1,y_1)??? and ???(x_2,y_2)???, then

???\int_C\bold{F}\cdot d\bold{r}=\int_C\nabla f\cdot d\bold{r}???

???=f(\bold{r}(b))-f(\bold{r}(a))???

???=f(x_2,x_1)-f(y_2,y_1)???

 
 

How to determine whether or not the line integral is independent of path


 
Krista King Math Signup.png
 
Calculus 3 course.png

Take the course

Want to learn more about Calculus 3? I have a step-by-step course for that. :)

 
 

 
 
Krista King.png